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path: root/drivers/ata/libata-core.c
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Diffstat (limited to 'drivers/ata/libata-core.c')
-rw-r--r--drivers/ata/libata-core.c17
1 files changed, 9 insertions, 8 deletions
diff --git a/drivers/ata/libata-core.c b/drivers/ata/libata-core.c
index 1687e24d3633..b079c3b5ec27 100644
--- a/drivers/ata/libata-core.c
+++ b/drivers/ata/libata-core.c
@@ -1571,7 +1571,8 @@ unsigned ata_exec_internal_sg(struct ata_device *dev,
int auto_timeout = 0;
struct ata_queued_cmd *qc;
unsigned int tag, preempted_tag;
- u32 preempted_sactive, preempted_qc_active;
+ u32 preempted_sactive;
+ u64 preempted_qc_active;
int preempted_nr_active_links;
DECLARE_COMPLETION_ONSTACK(wait);
unsigned long flags;
@@ -5195,7 +5196,7 @@ void __ata_qc_complete(struct ata_queued_cmd *qc)
* is called. (when rc != 0 and atapi request sense is needed)
*/
qc->flags &= ~ATA_QCFLAG_ACTIVE;
- ap->qc_active &= ~(1 << qc->tag);
+ ap->qc_active &= ~(1ULL << qc->tag);
/* call completion callback */
qc->complete_fn(qc);
@@ -5352,29 +5353,29 @@ void ata_qc_complete(struct ata_queued_cmd *qc)
* RETURNS:
* Number of completed commands on success, -errno otherwise.
*/
-int ata_qc_complete_multiple(struct ata_port *ap, u32 qc_active)
+int ata_qc_complete_multiple(struct ata_port *ap, u64 qc_active)
{
int nr_done = 0;
- u32 done_mask;
+ u64 done_mask;
done_mask = ap->qc_active ^ qc_active;
if (unlikely(done_mask & qc_active)) {
- ata_port_err(ap, "illegal qc_active transition (%08x->%08x)\n",
+ ata_port_err(ap, "illegal qc_active transition (%08llx->%08llx)\n",
ap->qc_active, qc_active);
return -EINVAL;
}
while (done_mask) {
struct ata_queued_cmd *qc;
- unsigned int tag = __ffs(done_mask);
+ unsigned int tag = __ffs64(done_mask);
qc = ata_qc_from_tag(ap, tag);
if (qc) {
ata_qc_complete(qc);
nr_done++;
}
- done_mask &= ~(1 << tag);
+ done_mask &= ~(1ULL << tag);
}
return nr_done;
@@ -5418,7 +5419,7 @@ void ata_qc_issue(struct ata_queued_cmd *qc)
}
qc->flags |= ATA_QCFLAG_ACTIVE;
- ap->qc_active |= 1 << qc->tag;
+ ap->qc_active |= 1ULL << qc->tag;
/*
* We guarantee to LLDs that they will have at least one