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author | Peter Zijlstra <peterz@infradead.org> | 2014-04-24 12:00:47 +0200 |
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committer | Ingo Molnar <mingo@kernel.org> | 2014-05-07 11:51:35 +0200 |
commit | 6ccdc84b81a0a6c09a7f0427761d2f8cecfc2218 (patch) | |
tree | a24ec143b5c4d36a8e4551cd8dd3015848e78bc7 /kernel | |
parent | 6227cb00cc120f9a43ce8313bb0475ddabcb7d01 (diff) | |
download | lwn-6ccdc84b81a0a6c09a7f0427761d2f8cecfc2218.tar.gz lwn-6ccdc84b81a0a6c09a7f0427761d2f8cecfc2218.zip |
sched: Skip double execution of pick_next_task_fair()
Tim wrote:
"The current code will call pick_next_task_fair a second time in the
slow path if we did not pull any task in our first try. This is
really unnecessary as we already know no task can be pulled and it
doubles the delay for the cpu to enter idle.
We instrumented some network workloads and that saw that
pick_next_task_fair is frequently called twice before a cpu enters
idle. The call to pick_next_task_fair can add non trivial latency as
it calls load_balance which runs find_busiest_group on an hierarchy of
sched domains spanning the cpus for a large system. For some 4 socket
systems, we saw almost 0.25 msec spent per call of pick_next_task_fair
before a cpu can be idled."
Optimize the second call away for the common case and document the
dependency.
Reported-by: Tim Chen <tim.c.chen@linux.intel.com>
Signed-off-by: Peter Zijlstra <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Len Brown <len.brown@intel.com>
Link: http://lkml.kernel.org/r/20140424100047.GP11096@twins.programming.kicks-ass.net
Signed-off-by: Ingo Molnar <mingo@kernel.org>
Diffstat (limited to 'kernel')
-rw-r--r-- | kernel/sched/core.c | 10 |
1 files changed, 8 insertions, 2 deletions
diff --git a/kernel/sched/core.c b/kernel/sched/core.c index e62c65a12d5b..28921ec91b3d 100644 --- a/kernel/sched/core.c +++ b/kernel/sched/core.c @@ -2592,8 +2592,14 @@ pick_next_task(struct rq *rq, struct task_struct *prev) if (likely(prev->sched_class == class && rq->nr_running == rq->cfs.h_nr_running)) { p = fair_sched_class.pick_next_task(rq, prev); - if (likely(p && p != RETRY_TASK)) - return p; + if (unlikely(p == RETRY_TASK)) + goto again; + + /* assumes fair_sched_class->next == idle_sched_class */ + if (unlikely(!p)) + p = idle_sched_class.pick_next_task(rq, prev); + + return p; } again: |