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authorChris Mason <chris.mason@oracle.com>2008-04-14 09:46:10 -0400
committerChris Mason <chris.mason@oracle.com>2008-09-25 11:04:01 -0400
commit98d20f67cf99ccda638dbcdf7b3a9ee0a428d932 (patch)
tree2cd417558d34777ee8aabc950ccc0993d542d1b0 /fs/btrfs/inode.c
parent73f61b2a6459df982cb4faf0e5cf5ac8b153aaff (diff)
downloadlwn-98d20f67cf99ccda638dbcdf7b3a9ee0a428d932.tar.gz
lwn-98d20f67cf99ccda638dbcdf7b3a9ee0a428d932.zip
Add a min size parameter to btrfs_alloc_extent
On huge machines, delayed allocation may try to allocate massive extents. This change allows btrfs_alloc_extent to return something smaller than the caller asked for, and the data allocation routines will loop over the allocations until it fills the whole delayed alloc. Signed-off-by: Chris Mason <chris.mason@oracle.com>
Diffstat (limited to 'fs/btrfs/inode.c')
-rw-r--r--fs/btrfs/inode.c2
1 files changed, 2 insertions, 0 deletions
diff --git a/fs/btrfs/inode.c b/fs/btrfs/inode.c
index 46f54dfa2b0a..7869c0157a1f 100644
--- a/fs/btrfs/inode.c
+++ b/fs/btrfs/inode.c
@@ -125,6 +125,7 @@ static int cow_file_range(struct inode *inode, u64 start, u64 end)
while(num_bytes > 0) {
cur_alloc_size = min(num_bytes, root->fs_info->max_extent);
ret = btrfs_alloc_extent(trans, root, cur_alloc_size,
+ root->sectorsize,
root->root_key.objectid,
trans->transid,
inode->i_ino, start, 0,
@@ -133,6 +134,7 @@ static int cow_file_range(struct inode *inode, u64 start, u64 end)
WARN_ON(1);
goto out;
}
+ cur_alloc_size = ins.offset;
ret = btrfs_insert_file_extent(trans, root, inode->i_ino,
start, ins.objectid, ins.offset,
ins.offset);