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authorAlexander Kapshuk <alexander.kapshuk@gmail.com>2015-10-12 21:39:46 +0300
committerGreg Kroah-Hartman <gregkh@linuxfoundation.org>2015-10-17 21:55:26 -0700
commita8782227598084d95358c08a6d3d6ea84422af11 (patch)
treeed40927de69eed9a6c96b520876572738e4b6ca3
parent5bcb2f59240cb5501956f2a089ba82e0b8621564 (diff)
downloadlwn-a8782227598084d95358c08a6d3d6ea84422af11.tar.gz
lwn-a8782227598084d95358c08a6d3d6ea84422af11.zip
ver_linux: e2fsprogs, look for numerical input, not field number
Rely on regex to find the version number, rather than rely on numerical input to be found in a particular input field. Proposed implementation also eliminates the necessity to invoke 'grep' + 'sed' + 'awk'. Tested on: Gentoo Linux Debian 6.0.10 Oracle Linux Server release 7.1 Signed-off-by: Alexander Kapshuk <alexander.kapshuk@gmail.com> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
-rwxr-xr-xscripts/ver_linux8
1 files changed, 6 insertions, 2 deletions
diff --git a/scripts/ver_linux b/scripts/ver_linux
index 7cc74d15e7f1..2e1929f2c9de 100755
--- a/scripts/ver_linux
+++ b/scripts/ver_linux
@@ -46,8 +46,12 @@ awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
substr($0,RSTART,RLENGTH))
}'
-tune2fs 2>&1 | grep "^tune2fs" | sed 's/,//' | awk \
-'NR==1 {print "e2fsprogs ", $2}'
+tune2fs 2>&1 |
+awk '/^tune2fs/{
+ match($0, /[0-9]+([.]?[0-9]+)+/)
+ printf("E2fsprogs\t\t%s\n",
+ substr($0,RSTART,RLENGTH))
+}'
fsck.jfs -V 2>&1 | grep version | sed 's/,//' | awk \
'NR==1 {print "jfsutils ", $3}'